This is the first article on the new awk tutorial series. We’ll be posting several articles on awk in the upcoming weeks that will cover all features of awk with practical examples.
In this article, let us review the fundamental awk working methodology along with 7 practical awk print examples.
Note: Make sure you review our earlier Sed Tutorial Series.
Awk Introduction and Printing Operations
Awk is a programming language which allows easy manipulation of structured data and the generation of formatted reports. Awk stands for the names of its authors “Aho, Weinberger, and Kernighan”
The Awk is mostly used for pattern scanning and processing. It searches one or more files to see if they contain lines that matches with the specified patterns and then perform associated actions.
Some of the key features of Awk are:
- Awk views a text file as records and fields.
- Like common programming language, Awk has variables, conditionals and loops
- Awk has arithmetic and string operators.
- Awk can generate formatted reports
Awk reads from a file or from its standard input, and outputs to its standard output. Awk does not get along with non-text files.
Syntax:
awk '/search pattern1/ {Actions}
/search pattern2/ {Actions}' file
In the above awk syntax:
- search pattern is a regular expression.
- Actions – statement(s) to be performed.
- several patterns and actions are possible in Awk.
- file – Input file.
- Single quotes around program is to avoid shell not to interpret any of its special characters.
Awk Working Methodology
- Awk reads the input files one line at a time.
- For each line, it matches with given pattern in the given order, if matches performs the corresponding action.
- If no pattern matches, no action will be performed.
- In the above syntax, either search pattern or action are optional, But not both.
- If the search pattern is not given, then Awk performs the given actions for each line of the input.
- If the action is not given, print all that lines that matches with the given patterns which is the default action.
- Empty braces with out any action does nothing. It wont perform default printing operation.
- Each statement in Actions should be delimited by semicolon.
Let us create employee.txt file which has the following content, which will be used in the
examples mentioned below.
$cat employee.txt 100 Thomas Manager Sales $5,000 200 Jason Developer Technology $5,500 300 Sanjay Sysadmin Technology $7,000 400 Nisha Manager Marketing $9,500 500 Randy DBA Technology $6,000
Awk Example 1. Default behavior of Awk
By default Awk prints every line from the file.
$ awk '{print;}' employee.txt
100 Thomas Manager Sales $5,000
200 Jason Developer Technology $5,500
300 Sanjay Sysadmin Technology $7,000
400 Nisha Manager Marketing $9,500
500 Randy DBA Technology $6,000
In the above example pattern is not given. So the actions are applicable to all the lines.
Action print with out any argument prints the whole line by default. So it prints all the
lines of the file with out fail. Actions has to be enclosed with in the braces.
Awk Example 2. Print the lines which matches with the pattern.
$ awk '/Thomas/ > /Nisha/' employee.txt 100 Thomas Manager Sales $5,000 400 Nisha Manager Marketing $9,500
In the above example it prints all the line which matches with the ‘Thomas’ or ‘Nisha’. It has two patterns. Awk accepts any number of patterns, but each set (patterns and its corresponding actions) has to be separated by newline.
Awk Example 3. Print only specific field.
Awk has number of built in variables. For each record i.e line, it splits the record delimited by whitespace character by default and stores it in the $n variables. If the line has 4 words, it will be stored in $1, $2, $3 and $4. $0 represents whole line. NF is a built in variable which represents total number of fields in a record.
$ awk '{print $2,$5;}' employee.txt
Thomas $5,000
Jason $5,500
Sanjay $7,000
Nisha $9,500
Randy $6,000
$ awk '{print $2,$NF;}' employee.txt
Thomas $5,000
Jason $5,500
Sanjay $7,000
Nisha $9,500
Randy $6,000
In the above example $2 and $5 represents Name and Salary respectively. We can get the Salary using $NF also, where $NF represents last field. In the print statement ‘,’ is a concatenator.
Awk Example 4. Initialization and Final Action
Awk has two important patterns which are specified by the keyword called BEGIN and END.
Syntax:
BEGIN { Actions}
{ACTION} # Action for everyline in a file
END { Actions }
# is for comments in Awk
Actions specified in the BEGIN section will be executed before starts reading the lines from the input.
END actions will be performed after completing the reading and processing the lines from the input.
$ awk 'BEGIN {print "Name\tDesignation\tDepartment\tSalary";}
> {print $2,"\t",$3,"\t",$4,"\t",$NF;}
> END{print "Report Generated\n--------------";
> }' employee.txt
Name Designation Department Salary
Thomas Manager Sales $5,000
Jason Developer Technology $5,500
Sanjay Sysadmin Technology $7,000
Nisha Manager Marketing $9,500
Randy DBA Technology $6,000
Report Generated
--------------
In the above example, it prints headline and last file for the reports.
Awk Example 5. Find the employees who has employee id greater than 200
$ awk '$1 >200' employee.txt 300 Sanjay Sysadmin Technology $7,000 400 Nisha Manager Marketing $9,500 500 Randy DBA Technology $6,000
In the above example, first field ($1) is employee id. So if $1 is greater than 200, then just do the default print action to print the whole line.
Awk Example 6. Print the list of employees in Technology department
Now department name is available as a fourth field, so need to check if $4 matches with the string “Technology”, if yes print the line.
$ awk '$4 ~/Technology/' employee.txt 200 Jason Developer Technology $5,500 300 Sanjay Sysadmin Technology $7,000 500 Randy DBA Technology $6,000
Operator ~ is for comparing with the regular expressions. If it matches the default action i.e print whole line will be performed.
Awk Example 7. Print number of employees in Technology department
The below example, checks if the department is Technology, if it is yes, in the Action, just increment the count variable, which was initialized with zero in the BEGIN section.
$ awk 'BEGIN { count=0;}
$4 ~ /Technology/ { count++; }
END { print "Number of employees in Technology Dept =",count;}' employee.txt
Number of employees in Tehcnology Dept = 3
Then at the end of the process, just print the value of count which gives you the number of employees in Technology department.
Recommended Reading
Sed and Awk 101 Hacks, by Ramesh Natarajan. I spend several hours a day on UNIX / Linux environment dealing with text files (data, config, and log files). I use Sed and Awk for all my my text manipulation work. Based on my Sed and Awk experience, I’ve written Sed and Awk 101 Hacks eBook that contains 101 practical examples on various advanced features of Sed and Awk that will enhance your UNIX / Linux life. Even if you’ve been using Sed and Awk for several years and have not read this book, please do yourself a favor and read this book. You’ll be amazed with the capabilities of Sed and Awk utilities.
Additional Awk Articles
- Awk User-defined Variables with 3 Practical Examples
- 8 Powerful Awk Built-in Variables – FS, OFS, RS, ORS, NR, NF, FILENAME, FNR
- 7 Powerful Awk Operators Examples (Unary, Binary, Arithmetic, String, Assignment, Conditional, Reg-Ex Awk Operators)
- 4 Awk If Statement Examples ( if, if else, if else if, : ? )
- Caught In the Loop? Awk While, Do While, For Loop, Break, Continue, Exit Examples
My name is Ramesh Natarajan. I will be posting instruction guides, how-to, troubleshooting tips and tricks on Linux, database, hardware, security and web. My focus is to write articles that will either teach you or help you resolve a problem. Read more about
Comments on this entry are closed.
I have only just started reading these articles. So far I think they are well written and the explanations are clearly done with an awareness as to how they might possibly be misunderstood and hence extra layers of detail are presented where that might happen. For example, pointing out that the tilde (~) is used to compare with regular expressions when the reader might have otherwise expected an equals sign – without the explanation the reader might have decided that the tilde represented the same thing as an equals sign.
I shall be reading more.
Thanks for posting these articles.
Kind Regards
Steve
Thank you for the post here on awk. I use it frequently, but it is always good to have some updates and reminders. Happy New Year.
awk is awesome! thanks for your sharing.
Best Regards,
Lawrence
Hi… Good article – now I know what ark is, and what I could use it for – well written…. I follow you now on twitter!
Thanks for posting a tutorial on awk with illustrated examples.
I Will be expecting other articles on awk 🙂
@Steve,
Yeah. ~ can be little confusing in this context, if not explained properly. Thanks for you comment.
@Daniel,
Yeah. Most other readers of the blog are in similar position like you. So, we are here to give constant updated and remainders of the functionality that they already know.
@Lawrence, Harsh,
Thanks for the very nice comment. I’m glad you liked this article.
@Knusper,
Thanks for following us on twitter.
Nandraka Ulladhu!!!
I guess the example 2 can be done without a new line like below? Pattern as regex.
~/bin$ awk ‘/Jason|Randy/’ employee
200 Jason Developer Technology $5,500
500 Randy DBA Technology $6,000
And also what does the ; stands for? End of Pattern?
Hi,
I want to use an if else statement like this:
if $10>10 print $0 > filename1
else print $0> filename2
but it’s not working it is not creating filename1 or filename2, how can I do this?
thanks?
Grt post.Thanks for making me understand the awk working
hi, this is avinash….
suppose u have a emp table like this:
id name designation salary
1 avi manager 1000
2 ash manager 1500
3 nash manager 2000
4 varma trainee 500
5 chow trainee 600
6 hemanth trainee 800
using awk command, i hav to print manager total salary and trainee total salary….
i need a program….. can any one plz post it
Hi…..@Avinash…..
u can try this one…….
awk ‘BEGIN {man_sal=0;trainee_sal=0;}
$3 ~/manager/ {man_sal+=$NF}
/trainee/ {trainee_sal+=$NF}
END {print “Total salary of manager’s and trainee’s are=”man_sal,trainee_sal}’ in_file.name
Hello forum members,
Thanks for AWK tutorials ,it was very help ful to me.
@ vikas
thanks you
hi all,
if i have a issue file like:
101 add open vish iuo
if exit and login again i should get the increment of the first field like
102 add open vish iuo
its simply superb to understand
its is very useful for the beginning learners and its is very help in exams time also
so guys read and enjoy wd the unix
This is very help. How about if I want to print the salary seperated by commas, e.g. 2,000 instead of 2000
You’ve made a little typo:
> Number of employees in _Tehcnology_ Dept = 3
vary vary healpul to every one
Its very useful for beginers like me…………
Hi,
I found this article to be very useful. Anybody who wants to know what an awk is , this will give a fair idea. Looking forward to similar articles on other topics of unix.
Thanks 🙂
Hi,
Good,
Please try teach in Youtube to try differntly.
It will be more success.
Keep it up,
I need to take an exam on awk, let me see how much I can successed.
very simple and easy to understand, thanks a lot, it help me a lot
good simple article 🙂
I have read few geekstuff articles until now, explanations provided are the best I have ever seen so far! Great job 🙂 Thanks a lot 🙂
hi,
i have the question that how to using print command “awk” to sort or transpose this data from many coloums to 2 columns only
#input file
NAME JAN FEB MARCH APRIL MAY JUNE JULY
——- —– —— ———- ——– —— ——- ——
BEN 5,000 6,000 7,000 8,000 6,500 7,500 9,000
YONG 4,000 5,500 6,000 5,800 7,000 8,000 8,5000
# output should be as below.
BEN 5,000
BEN 6,000
BEN 7,000
BEN 8,000
BEN 6,500
BEN 7,500
BEN 9,000
YONG 4,000
YONG 5,500
YONG 6,000
YONG 5,800
YONG 7,000
YONG 8,000
YONG 8,5000
Anyone can help.thanks
@muss
I know it’s late, but …
#!/bin/bash
awk ‘ {
# skip the first two lines
if (NR == 1 || NR == 2)
continue
for(i=2; i<=NF; i++)
printf("%s %s\n", $1, $i)
} ' datafile.txt
Nice site! I learned some new things about sed I didn't know.
The article is simply awesome!!!
Very gud information for beginners. Thanks
We have duplicate titles in our library database. I am able to find the duplicates but can’t figure out how to print the line above that matches the regular expression and that line also has the same expression. Each set of duplicates has a space between: example. I would match on SERSOL-EBK
2012 Joe ate my dog|SERSOL-EBK|122456
2012 Joe ate my dog|SERSOL-EBK|122459
2011 Joe ate my toaster|SERSOL-EBK|122433
2011 Joe ate my toaster|SERSOL-EBK|125567
hi..
i want to capture these data through awk.
596583.46875(E) 4924298.34375(N)
geology@PERMANENT in PERMANENT (9)sand
604960.78125(E) 4922837.53125(N)
geology@PERMANENT in PERMANENT (6)shale
596911.40625(E) 4920512.15625(N)
geology@PERMANENT in PERMANENT (4)sandstone
the output should be :
insert into mytable values(596583.46875,4924298.34375,geology@PERMANENT,shale);
insert into mytable values(604960.78125,4922837.53125,geology@PERMANENT,shale);
any help would be grateful.
—
sorry i need to put shale within single codes so that i can insert into my table.insert into mytable values(596583.46875,4924298.34375,geology@PERMANENT,’shale’);
—
Thank u
Great article. Thanks you 🙂
Thank you for this site – you really saved me a lot of time. This is easy to follow and really helped me understand awk.
Hi All,
I have a log file with the contents as below.
09:30:51 [00082] TIMER iatesystems.hub.logging.TimerLog: MPI_MxmRunMatch: 09:30:52 [00082] TIMER iatesystems.hub.logging.TimerLog: MPI_MxmRunMatch:
09:30:53 [00082] TIMER iatesystems.hub.logging.TimerLog: MPI_MxmRunMatch:
This will have entities based on the timestamp shown above (i.e. 09:30:51, 09:30:52, etc).
Now my requirement is, I need to get the number of entries per an hour.
For example if the first record is with timestamp as 09:30:51.
Till 10:30:51 timestamp’s record I need to get the number of records.
Can you please help me to get this?
Thanks,
Sudarshan
Neha try this
suppose your data filename=log.txt
insert statements be put in insert.sql
————————————————————-
awk ‘BEGIN {str=”insert into mytable values(“;}
{if ((NR % 3)==1)
{ #print “NR1 is:” NR;
instr=str””substr($1,1,12)”,”substr($2,1,13);
#print “str1 is:” instr;
}
else if ((NR % 3)==2)
{#print “NR2 is:”NR;
instr=instr”,”$1″,””‘”‘”‘””ashale””‘”‘”‘””)”;
print instr >”insert.sql”;
}
else ((NR % 3)==0)
{# print “NR3 is:”NR;
str=”insert into mytable values(“;
}
fi}
END{}’ log.txt
Comma delimited file in below format
Name, Address,Start_Date,End_date
But for few records there is extra comma in the Address field
As
Mark, 110A , Stuart Mark, 01/01/2012,06/07/2012
Please help me as how to remove this extra comma, Out of 1 million record am having this issue in 10000 records
Prabhu:
If the number of fields is greater than 4, assume there is comma that makes field 2 into field 2 and field 3. Then, combine field 2 into field 2 and field 3:
awk ‘ BEGIN { FS=OFS=”,” }
{
if(NF > 4)
$2=”$2 $3″
print $0
} ‘ datafile.txt
Thanks Nalis, Appreciate your help
It is really very helpfull for beginers.i really appreciate you for sharing this info.
Thanks,
Kiran Indrala
Hello,
I have the following output:
[Server, Modul, Version, timestamp]
Serversv10 ;admin ;1.0.2 ;2012.12.03-14:07:39
Serversv10 ;admin ;0.1.2 ;2012.12.03-14:07:39
Serversv10 ;admin ;0.0.1 ;2012.12.04-09:29:45
Serversv10 ;admin ;0.0.12 ;2012.12.03-10:23:31
Serversv10 ;admin ;0.0.2 ;2012.12.03-14:07:39
Serversv10 ;admin ;1.0.1 ;2012.12.04-09:29:45
Serversv10 ;admin ;0.0.8 ;2012.12.04-09:34:39
Serversv10 ;project ;0.0.1 ;2012.12.03-14:08:37
Serversv11 ;admin ;0.0.6 ;2012.12.03-10:23:31
Serversv10 ;project ;0.0.1 ;2012.12.04-08:22:09
Serversv11 ;admin ;0.0.6 ;2012.12.03-13:58:58
Serversv11 ;admin ;0.0.6 ;2012.12.03-11:39:15
Serversv11 ;admin ;0.0.7 ;2012.12.03-14:07:39
Serversv11 ;basis ;0.0.1 ;2012.12.03-11:39:59
Serversv11 ;project ;0.0.1 ;2012.12.03-12:08:48
Serversv11 ;project ;0.0.1 ;2012.12.03-14:08:37
Serversv12 ;admin ;0.0.6 ;2012.12.03-10:23:31
Serversv12 ;admin ;0.0.6 ;2012.12.03-11:47:35
Serversv11 ;project ;0.0.1 ;2012.12.03-12:08:31
Serversv12 ;admin ;0.0.7 ;2012.12.03-14:07:39
Serversv12 ;basis ;0.0.1 ;2012.12.03-12:06:45
Serversv12 ;config ;0.0.1 ;2012.12.03-12:04:57
Serversv12 ;admin ;0.0.6 ;2012.12.03-13:58:58
and want to sort it as follows
[Server, Modul, Version, timestamp]
Serversv10 ;admin ;1.0.2 ;2012.12.03-14:07:39
Serversv10 ;admin ;0.1.2 ;2012.12.03-14:07:39
Serversv10 ;admin ;0.0.12 ;2012.12.03-10:23:31
Serversv10 ;admin ;0.0.8 ;2012.12.04-09:34:39
Serversv10 ;admin ;0.0.2 ;2012.12.03-14:07:39
Serversv10 ;project ;1.0.1 ;2012.12.03-14:08:37
Serversv10 ;project ;0.0.1 ;2012.12.03-14:08:37
the rest with the same order
Can you please help?
R.S.
Sorry, but I do not see a consistent sort order for your output. Please clarify exactly what you want.
Anyway, the Unix/Linux sort command might do what you want. Assuming the field seperator is a semi-colon, this command sorts by the first field, then the second, and then the fourth (the time stamp)
sort -t “;” -k 1,1 -k 2,2 -k 4,4 file.txt
I am having files in below format
2012-04-30 00:00:05,266 1335692570491, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 12486685 / 2012-04-30 00:00:05.196
2012-04-30 00:00:05,313 1335692570492, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 12486685 / 2012-04-30 00:00:05.260
2012-04-30 00:00:12,740 1335692570493, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 83022172 / 2012-04-30 00:00:12.687
2012-04-30 00:00:12,868 1335692570494, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 83022172 / 2012-04-30 00:00:12.822
2012-04-30 23:59:15,450 1335692590664, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 1437954504 / 2012-04-30 23:59:15.404
2012-04-30 23:59:15,645 1335692590665, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 200178220 / 2012-04-30 23:59:15.600
2012-04-30 23:59:17,177 1335692590666, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 1437954504 / 2012-04-30 23:59:17.128
2012-04-30 23:59:18,574 1335692590667, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 200178220 / 2012-04-30 23:59:18.513
2012-04-30 23:59:21,322 1335692590668, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 200178220 / 2012-04-30 23:59:21.274
2012-04-30 23:59:34,467 1335692590669, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 228289416 / 2012-04-30 23:59:34.410
2012-04-30 23:59:34,493 1335692590670, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 228289416 / 2012-04-30 23:59:34.434
2012-04-30 23:59:40,094 1335692590671, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 1195793760 / 2012-04-30 23:59:40.054
2012-04-30 23:59:40,168 1335692590672, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 1195793760 / 2012-04-30 23:59:40.127
2012-04-30 23:59:40,560 1335692590673, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CHECK_REQ / 1195793760 / 2012-04-30 23:59:40.523
2012-04-30 23:59:41,289 1335692590674, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 1195793760 / 2012-04-30 23:59:41.011
2012-04-30 23:59:46,895 1335692590675, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 1174256481 / 2012-04-30 23:59:46.827
2012-04-30 23:59:46,914 1335692590676, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 1174256481 / 2012-04-30 23:59:46.841
2012-04-30 23:59:56,228 1335692590677, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_LIST_REQ / 298656228 / 2012-04-30 23:59:56.167
2012-04-30 23:59:58,399 1335692590678, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_LIST_REQ / 1181525888 / 2012-04-30 23:59:58.318
2012-04-30 23:59:58,499 1335692590679, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 298656228 / 2012-04-30 23:59:58.436
2012-04-30 23:59:58,661 1335692590681, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 298656228 / 2012-04-30 23:59:58.605
2012-04-30 23:59:58,663 1335692590680, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 298656228 / 2012-04-30 23:59:58.600
2012-04-30 23:59:58,706 1335692590682, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 298656228 / 2012-04-30 23:59:58.644
2012-04-30 23:59:58,971 1335692590683, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CHECK_REQ / 298656228 / 2012-04-30 23:59:58.902
2012-04-30 23:59:59,058 1335692590684, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_LIST_REQ / 1220865349 / 2012-04-30 23:59:59.010
2012-04-30 23:59:59,794 1335692590685, Request received from client :: Transaction / PRS_ID / Timestamp :: Amit_CARD_DATA_REQ / 1220865349 / 2012-04-30 23:59:59.741
now i want the output in below format
2012-04-30 | 2012-04-30 23:59:59 | 1335692590685 | Amit_CARD_DATA_REQ | 1220865349
1st field is extracted from the timestamp filed 2012-04-30 23:59:59
—
In the above the adjacent row will be present as a single row….While copying it in the website its getting split into 2 rows
—
Please help me on this
thanks,
Amit
Nice and simple article.
example 5 indicates print, angular brackets and ; are optional.. is that correct?
Best AWK introduction I’ve come across. Thanks!!
>K<
i want awk program to display employee details
Hi All,
I have a question on how to read n+ line in a file and substitute the data in a template file.Below is the example
**NAME**
ANNE 80
**Template.txt**
$NAME’s mark is $MARK.
I managed to read the data, substitute into the template and append to RESULT as below.
NAME=`awk ‘{print$1}’ NAME` ; MARK=`awk ‘{print$2}’ NAME`
sed -e “s|NAME|$NAME|” -e “s|MARK|$MARK|” Template.txt >> RESULT
The RESULT will be
ANNE’s mark is 80.
But when the are few rows of data, i dont know how to read the second line and the rest. I have 300 rows of data.
**NAME**
ANNE 80
SHAWN 30
NINA 50
Can anyone help me since im newbiew in scripting.
Thanks in advance 🙂
Hi all,
I have a doubt
I want to use a variable in the matching of regular expression field
i.e i am reading a string from the user and I want to match it in awk against the whole file
read var;
cat int_out.txt | awk /var instead of reg exp/ { print $1};
Can any1 help me regarding this
thanks
There are a number of ways of embedding a shell variable in an awk script. This link describes them:
http://tek-tips.com/faqs.cfm?fid=1281
Post a more descriptive example if you require more help. Thanks.
Nails.
way of explanation is really nice …. thanks a lot
thank you!
Worth reading and understandable, thanks a lot
i want to add zero in between character . how i ll do dat ?
How do I read a ( ` ) separated file using the awk command?? Can I read each column by column of the (`) delimited file??
Aravind:
Does your data file look like this (back tic delimited):
one`two`three
four`five`six
awk has an internal Field Seperator variable which allows to change the field delimiter:
#!/bin/bash
awk ‘ BEGIN { FS=”`” }
{
print $2 # print the second field
} ‘ datafile.txt
Hi,
below are the 2 lines from my log file:-
2013-05-14 12:40:06,524 (http-172.24.90.20-5555-17) [ LoginLogger.java:55 :INFO ] [Login ID:superadmin] [User ID:SU001] [Network ID:NG] [User Name:superadmin] [User Type:OPERATOR] [Category Code:SUADM] [Log Type:LOGIN] [Login Time:14/05/13 12:40:06] [Logout Time: ] [IP Address:172.16.100.11] [Browser Type:Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 6.1; Trident/5.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; InfoPath.2; .NET4.0C)] [Other Information:Successfully Login]
2013-05-14 13:04:43,797 (ContainerBackgroundProcessor[StandardEngine[Catalina]]) [ LoginLogger.java:55 :INFO ] [Login ID:netadm] [User ID:PT130306.1715.012115] [Network ID:NG] [User Name:Network Admin] [User Type:OPERATOR] [Category Code:NWADM] [Log Type:LOGOUT] [Login Time:14/05/13 11:26:03] [Logout Time:14/05/13 13:04:43] [IP Address:172.24.180.35] [Browser Type:Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 6.1; Trident/4.0; SLCC2; .NET CLR 2.0.50727; .NET CLR 3.5.30729; .NET CLR 3.0.30729; Media Center PC 6.0; InfoPath.3)] [Other Information:Logged Out successfuly]\
All lines are not same in my log file, Now my requirement is that i want only 5 fields from each line, and they are not on same place in all lines.
I want following fields in csv file Login ID,User Name,Log Type, Login Time, IP Address.
Thanks for your help.
Anshul:
Since the fields are not in order, I use a for loop to look at each field and match each of the 5 feilds you are interested in and then print out each of the 5 variables for each line processed:
awk ‘ BEGIN { FS=”[” ; myarr[1]=0}
{
loginid=””
username=””
logtype=””
logintime=””
ipaddress=””
for(i=1; i<=NF; i++)
{
if($i ~ /Login ID/)
{
sub("Login ID:","",$i) # delete the field identifier
sub("]","",$i) # delete the ]
sub(/[ \t]+$/, "", $i) # delete trailing whitespace
loginid=$i
}
if($i ~ /User Name/)
{
sub("User Name:","",$i) # delete the field identifier
sub("]","",$i) # delete the ]
sub(/[ \t]+$/, "", $i) # delete trailing whitespace
username=$i
}
if($i ~ /Log Type/)
{
sub("Log Type:","",$i) # delete the field identifier
sub("]","",$i) # delete the ]
sub(/[ \t]+$/, "", $i) # delete trailing whitespace
logtype=$i
}
if($i ~ /Login Time/)
{
sub("Login Time:","",$i)
sub("]","",$i) # delete the ]
sub(/[ \t]+$/, "", $i) # delete trailing whitespace
logintime=$i
}
if($i ~ /IP Address/)
{
sub("IP Address:","",$i) # delete the field identifier
sub("]","",$i) # delete the ]
sub(/[ \t]+$/, "", $i) # delete trailing whitespace
ipaddress=$i
}
}
printf("%s,%s,%s,%s,%s\n", loginid, username, logtype, logintime, ipaddress)
} ' logfile.txt
Nails:-
Thanks a lot for your wonderful scripts, it worked in one go. I am very oblidged for your kind help.
Anshul:
Thank you for the kind words. Much appreciated!
BTW, let me point out that by mistake I left an unused array declaration in the script:
myarr[1]=0
That can be deleted.
I have a log file and would like to count the number of the same value of first column,
for example count = 4 for -8.7, count = 4 for -7.8 … I am able to grep -v manually ; however, I would like to have the output as
cnt value …
4 -8.7
4 -7.8
1 -6.9
1 -2.5
2 -1.4
=========
input file
-8.7 check
-8.7 check
-8.7 check
-8.7 check
-7.8 check
-7.8 check
-7.8 check
-7.8 check
-6.9 check
-2.5 check
-1.4 check
-1.4 check
I would like to have the two line table from
BEN $5,000
BEN $6,000
BEN $7,000
BEN $8,000
BEN $6,500
BEN $7,500
BEN $9,000
YONG $4,000
YONG $5,500
YONG $6,000
YONG $5,800
YONG $7,000
YONG $8,000
YONG $8,5000
to
BEN 5,000 6,000 7,000 8,000 6,500 7,500 9,000
YONG 4,000 5,500 6,000 5,800 7,000 8,000 8,5000
Thanks as I am learning awk now
I am able to have the counting script
BEGIN { print “cnt “,”value” }
{
Slack[$1]++;
}
END {
for (var in Slack) {
print Slack[var],” “, var
}
}
and the output file looks like
cnt value
1
2 1.0
3 7.8
4 6.9
1 1.1
4 0.2
2 0.4
4 6.0
2 -0.0
1 -6.9
4 -7.8
4 -8.7
2 7.3
4 6.4
2 -0.5
2 -1.4
10 -0.7
1 -2.5
==========
my questions:
1) why I have the first line of “1” and no value? how to remove it?
2) how to do the print-out with the sorted column, for example, sort 1st column, sort 2nd column
Thx
First, you probably are getting the first line printed “1” because you have a line in the data file that is whitespace (space character, tab, or newline) . Get rid of it by including something like this in the first line of your awk script:
if(/^[ /t]*$/)
next
Second, the newer versions of GNU awk (such as gawk) has an internal sort routine called asort. Check it out at the GNU awk User’s Guide:
http://www.gnu.org/software/gawk/manual/gawk.html
Thanks for this. BEST AWK tutorial on the World Wide Web.
It seemed like an assembly language to me before I read this and after reading other tutorials, but yours has explained it in simple language and with easy examples to follow. Thanks!
Thanks for the Great article..
Here after I will tell to my friends, I know AWK utility.. Thanks again for the great article..
its very useful for our assignments thanks…………:-)
thank you its very helpful me
Hi all,
I was doing some string manipulation in my script and wanted to try using awk. However, I have been stuck with string compare. A simplified form of my conundrum is given below:
This works:
$ echo ‘”status”:”Completed”‘ | awk ‘BEGIN{FS=”:”} /”status”/ {print $2}’
“Completed” <– prints the correct word
This doesn't:
$ echo '"status":"Completed"' | awk 'BEGIN{FS=":"} /"status"/ {print ($2 == "Completed") ? "Yes" : "No"}'
No <– Shouldn't this output be Yes given $2 is "Completed"?
In the second one above, I'd have expected to see the output as "Yes" (since the second element is "Completed"), but it's been obstinately printing "No".
What am I doing wrong?
Btw, what I really need to do is set a variable if the string compare is successful. The print-test was just to see if it's work at all, and looks like I need to rethink.
Any help is highly appreciated.
this is my script
#!/bin/bash
KEEP=30 # days
SOURCE=/apps/tibco/domain/xxxxxxxx/xxxxxxxxx
DST=/apps/tibco/domain/xxxxxxxxxxxxxxxxxxxxxxxxxxx/xxxxxxx
for item in `find $SOURCE -type f -mtime +$KEEP | sed ‘s#.*/##”; do
DDATE=`stat –format=”%y” “$SOURCE/$item” | awk ‘{print $1}’
if [ -z “$DDATE” ]; then
continue
fi
# Make directory if needed
if [ -d “$DST/$DDATE” ]; then
mkdir “$DST/$DDATE”
fi
mv “$SOURCE/$item” “$DST/$DDATE/$item”
gzip “$DST/$DDATE/$item”
done
=========================================
Errors
./archive.sh: line 9: syntax error near unexpected token `|’
./archive.sh: line 9: ` DDATE=`stat –format=”%y” “$SOURCE/$item” | awk ‘{print $1}’`’
I have only one ` at the end of the line.
I see several problems with your script:
First, I see that your command subsitution isn’t correct; I choose to use the bash method of command substituion: $(….) instead of `…..`
for item in $(find for item in $(find $SOURCE -type f -mtime +$KEEP | sed ‘s#.*/##’)
do
Second, I thing you are mixing the quotation marks around the sed command.
Also, are you sure that your syntax for the stat command is correct? I thought the format keyword is used with the -c option.
Write an AWK command to list all the files except the one which is having name as “sample”
Write an AWK command to concatenate owner and group name of all the files in a directory.
Try these programs then type nawk -f circle or gawk -f circle).
Create file circle:
BEGIN { # circle nawk -f circle
do { loopCount++
system( “nawk -f s.circle” )
printf(“Another one? “)
getline
if ( $1 ~ /[Yy]/ ) { continue }
exit
} while ( loopCount )
}
END { # Display loop count
printf(“Ran circle %d times.\n”, loopCount)
}
Create file s.circle:
BEGIN { # s.circle
do { printf(“Type the radius ? “)
getline
r = $1 + 0
if ( r > 0 ) { exit }
printf(“Radius must be positive\n”)
} while ( 1 )
}
#
# Main
#
END { #
tau = 710 / 113
circumference = c = tau * r
printf(“The circumference is %f and the area is %f\n”, c, c * r / 2 )
}
Hi,
Good to learn.
Can you please provide the same understaindings for sed also
i need to concatenate 1st 4 characters of previous line to the next few lines.
How should I achieve this?
Thanks
Item 66, the close round bracket is in the wrong place, it should be:
nawk ‘/status/ {print ($2 == “Completed” ? “Yes” : “No” ) }’
and this works (produces “Yes”).
how do i convert the following
mira 23 43 56 abcd
mira 32 55 abcd xyz
raju 12 4a 5/7 4:4 abcd
raju 23 4r 3:4 ab
——————————————————–
to
Mira 23 43 56 abcd 32 55 abcd xyz
Raju 12 4a 5/7 4:4 abcd 23 4r 3:4 ab
————————————————————-
awk and print $1 can capture columns, but what about lines with same “name” in first columns to be grouped with all values in columns.
How about something like this? It’s a break point report that wipes out the first field until the first field changes:
#!/bin/bash
awk ‘ BEGIN { prevrec=”” ; fr=0 }
{
if(NF == 0)
next # skip blank lines
if(prevrec == “” || prevrec != $1)
{
prevrec=$1
if(fr == 0)
{
printf “\n%s”, $0
fr==0
}
else
{
$1=”” # wipe out the first field
printf ” %s”, $0
fr=1
}
}
else
{
$1=””
printf “%s”, $0
}
} END { printf “\n” } ‘ mytxt.txt
Thanks for the post, it helped me to give a start.
Can you provide me some of the basic questions, i can give a try..
Thanks in Advance,
Nikhil
Thanks for your info….I grew up in unix by reading your postss.Nice explanation …..Good work
Hi,
This output :
c1t50060E80166CED71d334s2
c1t50060E80166CED71d335s2
c1t50060E80166CED71d336s2
I want like this. i just want to remove last “s2” from every line.
Like this:
c1t50060E80166CED71d334
c1t50060E80166CED71d335
c1t50060E80166CED71d336
#Using sed:
sed ‘s/s2$//’ test.txt
# this works on my Solaris 9 box using nawk:
awk ‘ { sub(“s2$”, “”); print } ‘ test.txt
thanks a lot. its working fine
Hi
I have following file content and array of ids :
20140320 00:08:23.846 INFO [WebContainer : 84] – anything in line
20140320 00:08:23.846 Test [translate : 55] – Virtual and lab lab anything
20140320 00:08:23.846 Data [anything : 60] – anything in line
20140320 00:08:23.847 anyting [anything : 5] – anything in line
20140320 00:08:23.846 INFO [WebContainer : 84] – anything in line
20140320 00:08:23.846 Test [translate : 55] – Virtual and lab lab anything
20140320 00:08:23.846 Data [anything : 60] – anything in line
20140320 00:08:23.847 anyting [anything : 5] – anything in line
Suppose I have array elements 84 and 55 then only lines which has iside the brackets :
20140320 00:08:23.846 INFO [WebContainer : 84] – anything in line
20140320 00:08:23.846 Test [translate : 55] – Virtual and lab lab anything
20140320 00:08:23.846 INFO [WebContainer : 84] – anything in line
20140320 00:08:23.846 Test [translate : 55] – Virtual and lab lab anything
not sure how many elements are in array, but based on all the elements, lines should direct to output file
Please help me on this
One way is to read each line and use cut to save everything between the brackets. Then use the set command to perform the parsing. The last field can be determined with the eval command, and finally perform the comparison:
#!/bin/bash
while read line
do
orgline=”$line”
tt=$(echo $line|cut -d'[‘ -f2 | cut -d’]’ -f1)
set – $( echo “$tt”)
fvalue=$(eval echo “\$$#”)
if [[ $fvalue -eq 55 || $fvalue = 84 ]]
then
echo “$orgline”
fi
done < datafile.txt
Thanks nails,
I wanted to implement using awk, As there are more than 10000 of lines and this for look eating lot of times.
here no of threadid is also not fixed, I just gave two entry only it may be more.
Please suggest me
First, depending on the progamming implementation, don’t expext awk to be faster. As awk is an external command, an extra process is spawned.
I don’t understand:
“no of threadid is also not fixed”
Please post a better example of your data.
nails
thanks Nails,
The ThreadID is comming from other file as in array such as (55, 84) with two array elements. So here no of threadid, I mean no of elements are not fixed.
hi ,
I have two files as below
file 1
machine1 shutdown time 21:30:00
machine2 shutdown time 21:32:07
file 2:
machine1 started time 22:31:05
machine2 started time 21:30:25
now , i need a program, if shutdown time is less than started then print output as
“machine1/machine2 running as expected”
if shutdown time is greater than started time then print output as
“machine1/machine2 improper restart ”
thanks for help !
Hi Help,
I have an INPUT file shown below, I want to convert into the following output file as stated under the OUTPUT FILE.
Can anybody help me in awk scripts.
INPUT FILE
640 0.0 1480 1313.77 1500.09 1694.76 1536.66 1933.32 1583.61
2419.99 1699.16 2780.7 1872.48 3156.68 2020.53 4295.82 2596.38
5996.92 3417.41
960 0.0 1480 1500 1496.46 1758.46 1538.27 2061.54 1568.46
2381.54 1635.82 2741.54 1772.87 3283.08 2030.7 4295.82 2596.38
5998.46 3403.47
………………………………………………………………………………………………………………
…………………………………..
OUTPUT FILE:
640 0.0 1480
640 1313.77 1500.09
640 1694.76 1536.66
640 1933.32 1583.61
640 2419.99 1699.16
640 2780.7 1872.48
640 3156.68 2020.53
640 4295.82 2596.38
640 5996.92 3417.41
960 0.0 1480
960 1500 1496.46
960 1758.46 1538.27
960 2061.54 1568.46
960 2381.54 1635.82
960 2741.54 1772.87
960 3283.08 2030.7
960 4295.82 2596.38
960 5998.46 3403.47
………………………………………
………………………..
Thanks in Advance
Best Regards
Tanujib
How to (swap) column four to column two:
100 Thomas Manager Sales $5,000
200 Jason Developer Technology $5,500
300 Sanjay Sysadmin Technology $7,000
400 Nisha Manager Marketing $9,500
500 Randy DBA Technology $6,000
This is excellent. Thank you,.
Amit, I know a little late but here is the command u were looking for:
awk ‘{print $1″ | “$19” “substr($20,1,8) ” | “substr($3,1,length($3)-1) ” | ” $15″ |”$17}’ file1.txt
Hi Friends,
I did MCA 3 years back (due some problems i didnt do course)
can i get job in linux
i learning linux now
if any one guide me pls
Any idea on how to parse |+ as delimiter together. I have a file which looks like below
123|+MN|+2014
456|+DE|+2015
It is |+ separated file. But not able to process |+ as delimiter via awk…I want to parse and print third column i.e. which contains data points 2014 and 2015
any help would be really appreciated.
Great article, thank you!
Recently used AWK to get creation date of user by running:
sudo passwd -S sys | tail -1 | awk ‘{print $3}
Had to go through 50 servers one by one to get this info. I know with WMI in Windows I can create batch script to get system info.
Is it possible to run this script in Linux across more than one server with script or some kind of management tool?
Great article. Many Thanks 🙂
Hi Tanujib,
It is pretty late,but below command will give you the result
awk ‘{ for (i=2;i<=NF;i=i+2) {print $1,$i,$(i+1)}}'
Hi Sudarshan,
Since + is a special character it must be escaped,below will give you the desired result.
awk -F’|\\+’ ‘{print $3}’ <>
Hi fanyi,
Just swap while printing
awk ‘{print $1,$4,$3,$2,$5} <>
Hi ,
i have employee table like below.
100 Thomas Manager Sales $5,000
200 Jason Developer Technology $5,500
300 Sanjay Sysadmin Technology $7,000
400 Nisha Manager Marketing $9,500
500 Randy DBA Technology $6,000
i need data where $1=300 and $3=Sales (that is employee number 100 and dept is sales)
i want to compare two .csv files columnwise in unix using shell scripting
file1
METASRCID BMVTRID MersionID COUNTRY Curr
MET_CCD V14121011081 RECENT US USD
MET_CCD V141210110810 RECENT US USD
MET_CCD V141210110811 RECENT GB GBP
MET_CCD V141210110812 RECENT IE GBP
MET_CCD V141210110813 RECENT GB GBP
MET_CCD V141210110814 RECENT AU AUD
MET_CCD V141210110815 RECENT HK HKD
MET_CCD V141210110816 RECENT SG SGD
file2
METASRCID BMVTRID MersionID COUNTRY Curr
MET_CCD V14121011081 RECENT US USD
MET_CCD V141210110810 RECENT US USD
MET_CCD V141210110811 RECENT GB GBP
MET_CCD V141210110812 RECENT IE GBP
MET_CCD V141210110813 RECENT US GBP
MET_CCD V141210110814 RECENT AU AUD
MET_CCD V141210110818 RECENT HK HKD
MET_CCD V141210110816 RECENT SG SGD
output
msg: Files are not same
and changes in particular cell should get highlighted
MET_CCD V141210110813 RECENT “US” GBP
MET_CCD “V141210110818” RECENT HK HKD
Hi Ramana,
Below would work for you.
awk ‘($1==100 && $4==”Sales”)’ <>
Something like this would help
grep -Fxvf file1 file2
I have two csv files
error.csv
———————————————–
“Legacy ID”, “Message”
12222,”Pass”
12345,”Fail”
success.csv
———————————
“ID”,”Legacy ID”
1,12345
2,45678
I want to merge these two files and create one file as below
“ID”,”Legacy ID”,”Message”
”,12222,”Pass”
”,12345,”Fail”
1,12345,”
2,45678,”
I am new to linux, can you please help
Hi Surendra,
Below would work
awk ‘NR==FNR{print “\”””,”$0;next} {print $0″,””\””}’ error.csv success.csv
First print statement would print for first file and next print statement would print for the other file
how can I remove the duplicates
for example
col1 col2 col3
a x 10.3
a y 15.7
a x 14.3
b x 10.3
b y 15.7
b x 14.3
I would like to have as
a x 10.3
a y 15.7
b x 10.3
b y 15.7
meaning i want to have unique entries to col1 and col2.
Hi lily,
Below would work
awk ‘{k=$1$2;if(!a[k])a[k]=$0} END { for(k in a) {print a[k]} }’ <>
Nice article for someone new to awk
INPUT:
========
ilapp_cl1:stg_00 ilapp_ex1:stg_00_r 0:10:34
ilapp_cl1:test_00 ilapp_ex1:test_00_r 0:10:34
netezza_cl1:prod_00b netezza_ex1:prod_00b_r 0:20:33
oracore11g_cl1:ORPP2 oracore11g_ex1:ORPP2_r 9:5:37
oracore11g_cl1:ORPP2_arch oracore11g_ex1:ORPP2_arch_r 9:5:37
oracore11g_cl1:ORPP2_redo oracore11g_ex1:ORPP2_redo_r 9:5:37
vmcore_cl1:clc2_ds_1000 vmcore_ex1:clc2_dsr_1000 12:15:33
vmcore_cl1:clc2_ds_1001 vmcore_ex1:clc2_dsr_1001 12:15:34
vmcore_cl1:clc2_ds_1002 vmcore_ex1:clc2_dsr_1002 12:15:34
OUTPUT:
===========
Want to list the output of 3rd column first field is greater than 10 as I pasted below
vmcore_cl1:clc2_ds_1000 vmcore_ex1:clc2_dsr_1000 12:15:33
vmcore_cl1:clc2_ds_1001 vmcore_ex1:clc2_dsr_1001 12:15:34
vmcore_cl1:clc2_ds_1002 vmcore_ex1:clc2_dsr_1002 12:15:34
vmcore_cl1:clc2_ds_1003 vmcore_ex1:clc2_dsr_1003 12:15:34
awesome documennt on awk !!!
awk -F: ‘{split($3,aa,” “); if (aa[2] >10) print }’ 11.txt
awk -F: ‘{split($3,aa,” “); if (aa[2] >10) print }’ 11.txt
@
Rakesh
awk ‘{split($NF,blah,”:”)}{if (blah[1] > 10) {print }}’
Example 7
BEGIN statement is not necessary
just add 0 in END
very well explained ………..
Create a data file called employee in the format given below:
a. EmpCode Character
b. EmpName Character
c. Grade Character
d. Years of experience Numeric
e. Basic Pay Numeric
$vi employee
A001 ARJUN E1 01 12000.00
A006 Anand E1 01 12450.00
A010 Rajesh E2 03 14500.00
A002 Mohan E2 02 13000.00
A005 John E2 01 14500.00
A009 Denial SmithE2 04 17500.00
A004 Williams E1 01 12000.00
2.) Sort the file on EmpCode.
$cut –f1 employee | sort
Sort the file on EmpName.
$cut –f2 employee | sort
Sort the file on
(i) Decreasing order of basic pay
(ii) Increasing order of years of experience.
(i) $cut –f5 employee | sort –r
(ii) $cut –f4 employee | sort
Display the number of employees whose details are included in the file.
wc –l
Display all records with ‘smith’ a part of employee name.
cut –f2 –d “ ” employee | grep ‘^[smith]’ | wc –l
Display all records with EmpName starting with ‘B’.
$cut –f2 employee | grep ‘^[B]’ | wc –l
Display the records on Employees whose grade is E2 and have work experience of 2 to 5 years.
$cut –f3 employee | grep ‘[*2] | cut –f4 employee | grep ‘[2-5]’
Store in ‘file 1’ the names of all employees whose basic pay is between 10000 and 15000.
$cut –f2,5 employee | grep ‘[10000-15000]’ > rec
Display records of all employees who are not in grade E2.
$cut –f3 employee | grep ‘[*1]’
i want to print the table.in which i dont want to print 2 lines for that what command should i use…??/
@Arun M June 3, 2015, 9:18 pm
awk ‘match($3, /([0-9]+):[0-9]+:[0-9]+/, arr) && arr[1] > 10’ input_file
@ramana December 12, 2014, 10:59 am
awk ‘$1 == 300 && $4 == “Sales”‘ input_file
Another handy way to use awk is to determine the number of lines and store that into a variable
say your file (myFile.txt) contains
Line1
Line2
Line3
MYCOUNT=`wc -l myfile.txt | awk ‘{ print $1 }’ `
echo $MYCOUNT
will assign the number 3 to $MYCOUNT
Nice… awk example .. u have describe each example in simple way which easy to understand .
Very instructive post, thank you!
I was wondering how one can print the result of the query in a new file. I have a big datafile which I would like to separate in different smaller ones based on a certain column.
Thanks in advance!
Hello Ramesh:
Does awk process Unicode strings?
Thank you very much
Awesome Explanation.
I am looking for expert level training for shell scripting, will you be able to provide the same?
It was very useful as I am new to awkkkk..!!
Really nice …it helped me a lot…Thank You 🙂
I need your help with a minor change in a awk portion of a shell script to only generate log files larger than 500m….Keep in my that this script run on sun,aix, hpux and various flavors of unix and windows. Here is the script…
[.# command for gathering Listener Log
set v_listener_command “; echo ‘ Listener Log’ | tr ‘\\n’ ‘:’; echo ” | tr ‘\\n’ ‘ ‘ ; lsnrctl status | grep Log | awk ‘{ print \$4 }’ | sed ‘s/alert\\/log.xml/trace\\/listener.log/g’ | tr ‘\\n’ ‘ ‘; echo ‘-‘ | tr ‘\\n’ ‘ ‘ ; du -sk `lsnrctl status | grep Log | awk ‘{ print \$4 }’ | sed ‘s/alert\\/log.xml/trace\\/listener.log/g’` | awk ‘{if ( \$1 / 1024 + 0.5 >= 500 ) print $1 }’ | tr ‘\\n’ ‘ ‘ ; echo ‘(Mb)'”]
error:
——
can’t read “1”: no such variable
while executing
“set v_listener_command “; echo ‘ Listener Log’ | tr ‘\\n’ ‘:’; echo ” | tr ‘\\n’ ‘ ‘ ; lsnrctl status | grep Log | awk ‘{ print \$4 }’ | s…”
(file “/CTM/ctmuser/scripts/GetDBLog/exec_sshlogin_don.exp” line 101)